BETH A. SCOTT DO – NPI #1043256225
Radiology
A radiologist who utilizes x-ray, radionuclides, ultrasound and electromagnetic radiation to diagnose and treat disease.
BETH SCOTT is a radiologist located in PHILADELPHIA, PA. NPPES has assigned the NPI number 1043256225 to BETH SCOTT on June 22, 2006. It is a Type-1 NPI, indicating this NPI number is associated with an individual. The primary taxonomy selected by this provider is 2085R0202X from the Health Care Provider Taxonomy code set, which is classified as Radiology, specializing in Diagnostic Radiology
The NPI profile was previously updated about 13 years ago on Dec 19, 2012. Use the NPI data found here to bill health insurance companies, identify providers enrolled in Medicare and Medicaid services or other HIPAA compliant transactions. See the complete NPI profile for BETH SCOTT below.
NPI Profile for
BETH A. SCOTT
(about 20 years ago)
2 SCHIEDT
PHILADELPHIA, PA 19107 Phone: (215) 829-6079 Fax: (215) 829-7482
Identifiers for BETH SCOTT
Identifiers are used to associate other provider identifiers such as Medicaid or other insurers (ie:, Blue Cross, Blue Shield, Aetna, Kaiser-Permanente, etc.), with their NPI number. These identifiers can be used in matching an NPI number to an insurer's records. However, not all providers have such numbers and not all providers choose to include them in their NPI information.
| Description | Issuer | State | Identifier |
|---|---|---|---|
| MEDICAID | PA | 0016518850007 |
A taxonomy code is a code that describes the health care service provider's type, classification, and the area of specialization. The primary specialty for this provider is indicated as (Primary) below.
| Taxonomy Classification / Specialization | State | License |
|---|---|---|
| 2085R0202X - Radiology / Diagnostic Radiology (Primary) |
PA | OS005346L |
The taxonomy codes are selected by the provider at the time of NPI registration. Selection of a taxonomy code does not replace any credentialing or validation process that the provider requesting the code should complete.