CCRM DALLAS-FORT WORTH – NPI #1578049052
Obstetrics & Gynecology

An obstetrician/gynecologist who is capable of managing complex problems relating to reproductive endocrinology and infertility.

CCRM DALLAS-FORT WORTH is a provider located in FRISCO, TX. NPPES has assigned the NPI number 1578049052 to CCRM DALLAS-FORT WORTH on July 17, 2018. It is a Type-2 NPI, indicating this NPI number is associated with an organization. Since the name “CCRM DALLAS-FORT WORTH” is a dba name, the actual legal business name for this organization is CONCEPTIVE CARE. With multiple taxonomy codes selected, the primary taxonomy selected by this provider is 207VE0102X from the Health Care Provider Taxonomy code set, which is classified as Obstetrics & Gynecology, specializing in Reproductive Endocrinology

Use the NPI data found here to bill health insurance companies, identify providers enrolled in Medicare and Medicaid services or other HIPAA compliant transactions. See the complete NPI profile for CCRM DALLAS-FORT WORTH below.

NPI Profile for
CONCEPTIVE CARE

NPI Number
1578049052
Enumeration Date

(about 8 years ago)
Entity Type
Type-2  Organization
Organization health care providers may have a single employee or thousands of employees. An example is an incorporated individual who is an organization's only employee.
Legal Name
CONCEPTIVE CARE
Doing Business As (dba): CCRM DALLAS-FORT WORTH
Primary location
8380 WARREN PKWY STE 201
FRISCO, TX 75034-4199
Phone: (972) 377-2625 Fax:
Mailing address
Same as primary location
Organization Subpart
No
Authorized Official
DORETTE NOORHASAN
MANAGER
Phone: (972) 377-2625
Updated
Taxonomy Code(s)

A taxonomy code is a code that describes the health care service provider's type, classification, and the area of specialization. The primary specialty for this provider is indicated as (Primary) below.

The taxonomy codes are selected by the provider at the time of NPI registration. Selection of a taxonomy code does not replace any credentialing or validation process that the provider requesting the code should complete.