ALEXANDER J. CORDERO – NPI #1053112748
Internal Medicine

An internist who treats disorders of the kidney, high blood pressure, fluid and mineral balance and dialysis of body wastes when the kidneys do not function. This specialist consults with surgeons about kidney transplantation.

ALEXANDER CORDERO is a physician located in HUMACAO, PR. NPPES has assigned the NPI number 1053112748 to ALEXANDER CORDERO on March 20, 2025. It is a Type-1 NPI, indicating this NPI number is associated with an individual. The primary taxonomy selected by this provider is 207RN0300X from the Health Care Provider Taxonomy code set, which is classified as Internal Medicine, specializing in Nephrology

Use the NPI data found here to bill health insurance companies, identify providers enrolled in Medicare and Medicaid services or other HIPAA compliant transactions. See the complete NPI profile for ALEXANDER CORDERO below.

NPI Profile for
ALEXANDER J. CORDERO

NPI Number
1053112748
Enumeration Date

(more than a year ago)
Entity Type
Type-1  Individual (Male)
Legal Name
ALEXANDER J. CORDERO
Primary location
PALMAS PLANTATION
165, WEDGE ST
HUMACAO, PR 00791
Phone: (787) 398-3010 Fax:
Mailing address
Same as primary location
Sole Proprietor
Yes
Updated
Certification Date
Mar 18, 2025

Note: NPPES allows providers to attest to the accuracy of their NPI data. When a provider request any change to the NPI record, they will be able to attest to their changed NPI data, resulting in an updated certification date.

Taxonomy Code(s)

A taxonomy code is a code that describes the health care service provider's type, classification, and the area of specialization. The primary specialty for this provider is indicated as (Primary) below.

Taxonomy Classification / Specialization State License
207RN0300X
- Internal Medicine / Nephrology (Primary)
PR 7077380

The taxonomy codes are selected by the provider at the time of NPI registration. Selection of a taxonomy code does not replace any credentialing or validation process that the provider requesting the code should complete.