GOLDBERG, ROSENSTEIN, KHAN & FORMAN, M.D.PA. – NPI #1942497151
Internal Medicine
An internist who specializes in diagnosis and treatment of diseases of the digestive organs including the stomach, bowels, liver and gallbladder. This specialist treats conditions such as abdominal pain, ulcers, diarrhea, cancer and jaundice and performs complex diagnostic and therapeutic procedures using endoscopes to visualize internal organs.
GOLDBERG, ROSENSTEIN, KHAN & FORMAN, M.D.PA. is a provider located in TOWSON, MD. NPPES has assigned the NPI number 1942497151 to GOLDBERG, ROSENSTEIN, KHAN & FORMAN, M.D.PA. on October 02, 2007. It is a Type-2 NPI, indicating this NPI number is associated with an organization. The former legal business name for this organization is GOLDBERG, ROSENSTEIN & KHAN, M.D., P.A.. The primary taxonomy selected by this provider is 207RG0100X from the Health Care Provider Taxonomy code set, which is classified as Internal Medicine, specializing in Gastroenterology
The NPI profile was previously updated about 10 years ago on Oct 17, 2016. Use the NPI data found here to bill health insurance companies, identify providers enrolled in Medicare and Medicaid services or other HIPAA compliant transactions. See the complete NPI profile for GOLDBERG, ROSENSTEIN, KHAN & FORMAN, M.D.PA. below.
NPI Profile for
GOLDBERG, ROSENSTEIN, KHAN & FORMAN, M.D.PA.
(more than 18 years ago)
SUITE 502
TOWSON, MD 21204 Phone: (410) 296-4210 Fax: (410) 296-1489
PRESIDENT
Phone: (410) 296-4210
A taxonomy code is a code that describes the health care service provider's type, classification, and the area of specialization. The primary specialty for this provider is indicated as (Primary) below.
| Taxonomy Classification / Specialization | State | License |
|---|---|---|
| 207RG0100X - Internal Medicine / Gastroenterology (Primary) |
MD |
The taxonomy codes are selected by the provider at the time of NPI registration. Selection of a taxonomy code does not replace any credentialing or validation process that the provider requesting the code should complete.